### What Does The Law Of Cosines Reduce To When Dealing With A Right Triangle?

Now, let us suppose the triangle ABC is a right triangle having right angle at C. We can see that it reduces to Pythagoras Theorem. Hence, we can conclude that law of cosines reduce to Pythagoras Theorem when dealing with a right triangle

#### What does the law of cosines reduce to when dealing with a right angle?

Law of Cosines The Law of Cosines is used to find the remaining parts of an oblique (non-right) when either the lengths of two sides and the measure of the included angle is known (SAS) or the lengths of the three sides (SSS) are known. In either of these cases, it is impossible to use the because we cannot set up a solvable proportion.

• The Law of Cosines can also be stated as
• b 2 = a 2 + c 2 − 2 a c     cos B or
• a 2 = b 2 + c 2 − 2 b c     cos A,

Example 1: Two Sides and the Included Angle-SAS Given a = 11, b = 5 and m ∠ C = 20 °, Find the remaining side and angles.

1. c 2 = a 2 + b 2 − 2 a b     cos C
2. c = a 2 + b 2 − 2 a b     cos C
3.     = 11 2 + 5 2 − 2 ( 11 ) ( 5 ) ( cos 20 ° )
4. ≈ 6.53
5. To find the remaining angles, it is easiest to now use the Law of Sines.
6. sin A ≈ 11 sin 20 ° 6.53
7. A ≈ 144.82 °
8. sin B ≈ 5 sin 20 ° 6.53
9. B ≈ 15.2 °

Note that angle A is opposite to the longest side and the triangle is not a right triangle. So, when you take the inverse you need to consider the obtuse angle whose sine is 11 sin ( 20 ° ) 6.53 ≈ 0.5761, Example 2: Three Sides-SSS Given a = 8, b = 19 and c = 14, Find the measures of the angles. It is best to find the angle opposite the longest side first. In this case, that is side b,

• cos B = b 2 − a 2 − c 2 − 2 a c = 19 2 − 8 2 − 14 2 − 2 ( 8 ) ( 14 ) ≈ − 0.45089
• Since cos B is negative, we know that B is an obtuse angle.
• B ≈ 116.80 °
• Since B is an obtuse angle and a triangle has at most one obtuse angle, we know that angle A and angle C are both acute.
• To find the other two angles, it is simplest to use the Law of Sines.
• a sin A = b sin B = c sin C
• 8 sin A ≈ 19 sin 116.80 ° ≈ 14 sin C
• sin A ≈ 8 sin 116.80 ° 19
• A ≈ 22.08 °
• sin C ≈ 14 sin 116.80 ° 19
• C ≈ 41.12 °

: Law of Cosines

### What is the law of cosines right triangle?

The cosine of a right angle is 0, so the law of cosines, c 2 = a 2 + b 2 – 2ab cos C, simplifies to becomes the Pythagorean identity, c 2 = a 2 + b 2, for right triangles which we know is valid.

## Can the law of cosines be applied to right triangles?

The law of cosines applied to right triangles is the Pythagorean theorem, since the cosine of a right angle is 0. a2+b2−2abcosC⏟This is 0if C=90∘. =c2.

#### What does the cosine law give you?

Problem and Solution – Let us understand the concept by solving one of the cosines law problems. Problem: A triangle ABC has sides a=10cm, b=7cm and c=5cm. Now, find its angle ‘x’.

1. Solution:
2. Consider the below triangle as triangle ABC, where,
3. a=10cm
4. b=7cm
5. c=5cm

Law of Cosine Problems

• By using cosines law,
• a 2 = b 2 + c 2 – 2bc cos(x)
• Or
• cos x = (b 2 + c 2 – a 2 )/2bc
• Substituting the value of the sides of the triangle i.e a,b and c, we get
• cos(x) = (7 2 + 5 2 – 10 2 )/(2 × 7 × 5)
• cos(x)=(49 + 25 -100)/70
• cos(x)= -0.37
• It is important to solve more problems based on cosines law formula by changing the values of sides a, b & c and cross-check law of cosines calculator given above.

Law of cosines signifies the relation between the lengths of sides of a triangle with respect to the cosine of its angle. As per the cosine law, if ABC is a triangle and α, β and γ are the angles between the sides the triangle respectively, then we have: a 2 = b 2 + c 2 – 2bc cos α b 2 = a 2 + c 2 – 2ac cos β c 2 = b 2 + a 2 – 2ba cos γ where a,b, and c are the sides of the triangle.

1. The cosine law is used to determine the third side of a triangle when we know the lengths of the other two sides and the angle between them.
2. Law of cosine is not just restricted to right triangles, and it can be used for all types of triangles where we need to find any unknown side or unknown angle.
3. Cosine law is basically used to find unknown side of a triangle, when the length of the other two sides are given and the angle between the two known sides.

So by using the below formula, we can find the length of the third side: a 2 = b 2 + c 2 -2bc cos α Where a is the unknown side, b and c are the known sides of the triangle, and α is the angle between b and c. The formula to find the unknown angles using cosine law is given by: cos α = /2bc cos β = /2ac cos γ = /2ab : Law of Cosines ( Proof & Example)

### Why does the cosine decrease as the angle increases?

To better understand certain problems involving rockets and propulsion it is necessary to use some mathematical ideas from trigonometry, the study of triangles. Let us begin with some definitions and terminology which we will use on this slide. A right triangle is a three sided figure with one angle equal to 90 degrees.

1. A 90 degree angle is called a right angle which gives the right triangle its name.
2. We pick one of the two remaining angles and label it c and the third angle we label d,
3. The sum of the angles of any triangle is equal to 180 degrees.
4. If we know the value of c, we then know that the value of d : 90 + c + d = 180 d = 180 – 90 – c d = 90 – c We define the side of the triangle opposite from the right angle to be the hypotenuse,

It is the longest side of the three sides of the right triangle. The word “hypotenuse” comes from two Greek words meaning “to stretch”, since this is the longest side. We label the hypotenuse with the symbol h, There is a side opposite the angle c which we label o for “opposite”.

The remaining side we label a for “adjacent”. The angle c is formed by the intersection of the hypotenuse h and the adjacent side a, We are interested in the relations between the sides and the angles of the right triangle. Let us start with some definitions. We will call the ratio of the opposite side of a right triangle to the hypotenuse the sine and give it the symbol sin,

sin = o / h The ratio of the adjacent side of a right triangle to the hypotenuse is called the cosine and given the symbol cos, cos = a / h Finally, the ratio of the opposite side to the adjacent side is called the tangent and given the symbol tan, tan = o / a We claim that the value of each ratio depends only on the value of the angle c formed by the adjacent and the hypotenuse.

1. To demonstrate this fact, let’s study the three figures in the middle of the page.
2. In this example, we have an 8 foot ladder that we are going to lean against a wall.
3. The wall is 8 feet high, and we have drawn white lines on the wall and blue lines along the ground at one foot intervals.
4. The length of the ladder is fixed.

If we incline the ladder so that its base is 2 feet from the wall, the ladder forms an angle of nearly 75.5 degrees degrees with the ground. The ladder, ground, and wall form a right triangle. The ratio of the distance from the wall (a – adjacent), to the length of the ladder (h – hypotenuse), is 2/8 =,25.

• This is defined to be the cosine of c = 75.5 degrees.
• On another page we will show that if the ladder was twice as long (16 feet), and inclined at the same angle(75.5 degrees), that it would sit twice as far (4 feet) from the wall.
• The ratio stays the same for any right triangle with a 75.5 degree angle.) If we measure the spot on the wall where the ladder touches (o – opposite), the distance is 7.745 feet.

You can check this distance by using the Pythagorean Theorem that relates the sides of a right triangle: h^2 = a^2 + o^2 o^2 = h^2 – a^2 o^2 = 8^2 – 2^2 o^2 = 64 – 4 = 60 o = 7.745 The ratio of the opposite to the hypotenuse is,967 and defined to be the sine of the angle c = 75.5 degrees.

• Now suppose we incline the 8 foot ladder so that its base is 4 feet from the wall.
• As shown on the figure, the ladder is now inclined at a lower angle than in the first example.
• The angle is 60 degrees, and the ratio of the adjacent to the hypotenuse is now 4/8 =,5,
• Decreasing the angle c increases the cosine of the angle because the hypotenuse is fixed and the adjacent increases as the angle decreases.

If we incline the 8 foot ladder so that its base is 6 feet from the wall, the angle decreases to about 41.4 degrees and the ratio increases to 6/8, which is,75. As you can see, for every angle, there is a unique point on the ground that the 8 foot ladder touches, and it is the same point every time we set the ladder to that angle.

Mathematicians call this situation a function, The ratio of the adjacent side to the hypotenuse is a function of the angle c, so we can write the symbol as cos(c) = value, Notice also that as the cos(c) increases, the sin(c) decreases. If we incline the ladder so that the base is 6.938 feet from the wall, the angle c becomes 30 degrees and the ratio of the adjacent to the hypotenuse is,866.

Comparing this result with example two we find that: cos(c = 60 degrees) = sin (c = 30 degrees) sin(c = 60 degrees) = cos (c = 30 degrees) We can generalize this relationship: sin(c) = cos (90 – c) 90 – c is the magnitude of angle d, That is why we call the ratio of the adjacent and the hypotenuse the “co-sine” of the angle.

• Sin(c) = cos (d) Since the sine, cosine, and tangent are all functions of the angle c, we can determine (measure) the ratios once and produce tables of the values of the sine, cosine, and tangent for various values of c,
• Later, if we know the value of an angle in a right triangle, the tables will tell us the ratio of the sides of the triangle.

If we know the length of any one side, we can solve for the length of the other sides. Or if we know the ratio of any two sides of a right triangle, we can find the value of the angle between the sides. We can use the tables to solve problems. Some examples of problems involving triangles and angles include the forces on a model rocket during powered flight, the application of torques, and the resolution of the components of a vector. Guided Tours Activities: Related Sites: Rocket Index Rocket Home Beginner’s Guide Home Exploration Systems Mission Directorate Home

#### Is the Law of Cosines is applied to a right triangle the result is the same as the?

If the included angle is a right angle then the Law of Cosines is the same as the Pythagorean Theorem.

#### Can the Law of Sines be used to solve the given triangle?

The Law of Sines can be used to solve for the missing lengths or angle measurements in an oblique triangle as long as two of the angles and one of the sides are known.

#### In which case the Law of Cosines Cannot be used?

So you either need 2 sides and an angle to solve for the remaining side or all three sides to solve for an angle. So if you know two angles (which lets you figure out the third so technically three angles) and a side you can’t just use the law of cosines.

### Why do we need the law of cosines?

It is most useful for solving for missing information in a triangle. For example, if all three sides of the triangle are known, the cosine rule allows one to find any of the angle measures. Similarly, if two sides and the angle between them is known, the cosine rule allows one to find the third side length.

## Is cosine increasing or decreasing?

Cosine Function: f(x) = cos (x) decreasing on (0, π) increasing on (π, 2π).

## Why does cosine function decrease?

As θ increases from 0 to π, from the figure, x decreases from r to −r. Since cos(θ)=xr and r is fixed cos(θ) decreases as x decreases. Hence, cos(θ) decreases from 1 to −1 as θ increases from 0 to π.

## Does cosine increase with angle?

The One About Trigonometry | MCAT Tips and Tricks Last Updated on June 23, 2022 by I’m guessing that by this point in your MCAT preparation you feel like you’ve parked a dump truck full of information next to your desk and shoveled facts into your brain until its about ready to burst. And then you hit that physics problem.

The one that requires you to know the sine – or is that cosine? – of 60 degrees. You search through your mental hard drive for references to trigonometry. There’s something about SOH CAH TOA and a 2 and b 2, Oh dear. Something else to add to the “to memorize” list that’s growing to the thickness of your organic chemistry textbook.

There are lots of videos and articles about tricks for memorizing sine and cosine values, and they are a good starting point, but they aren’t actually that helpful for the MCAT. (We’ll see why later). All you really need to memorize to do any trigonometry calculation on test day is “syne – point 5, point 7, point 9”. In the picture below, we see two right triangles inscribed over a unit circle: one with its hypotenuse at an angle of 30° with the x-axis and one with its hypotenuse at an angle of 60° with the x-axis. Because sine = opposite/hypotenuse (SOH), the sine of an angle relates the length of the side of the triangle in the y-direction with the hypotenuse.

To remember this, it can be helpful to think of “sine” and “y” having similar sounds. That’s why we write “sine” as “syne” in the rhyme. As you increase the degree of the angle, the length of the triangle in the y-direction increases, as does the sine of the angle. Sin(0°) = 0 because the “triangle” would have no length in the y-direction, and sin(90°) = 1 because the “triangle” would have all of its length in the y-direction.

Cosine describes the ratio of the length of the triangle in the x-direction and follows a similar patter except backward. As the angle increases, the length of the triangle in the x-direction decreases, as does the cosine of the angle. The cosine of 0° = 1 and the cosine of 90° = 0. What about the values for sine and cosine for the rest of the angles? Here’s where the point 5, point 7, point 9 part of the rhyme come in. Let’s begin with sine or “syne” from the rhyme. The trick that people often teach to memorize the sine of common angles is to begin by writing an empty square root sign divided by 2. Now, under the square root sign, write the numbers 0, 1, 2, 3 and 4 in order. Some of these fractions simplify nicely to decimals, but the sine of 45° and 60° won’t. Most videos and articles teaching this topic leave you here, but because you don’t have the luxury of working with a calculator, memorizing quantities like doesn’t really help very much. It is better instead to memorize decimal approximations of and, which is where the rhyme comes in. ≈ 0.7 and ≈ 0.9. If you have to do a trig calculation with a sine, you can quickly jot down sin(0°) = 0, sin(90°) = 1 and remember the rhyme, “syne – point 5, point 7, point 9” (again “syne” because sine is telling us about the y-direction of the triangle).

If you look back at the unit circle, you see that the cosine values for each of these angles are just the reverse of the sine values. So the cosine of 0° = 1, cosine of 30° = 0.9, etc. If you need the cosine, you can just jot down the values of sine and then put them in the reverse order, no memorization necessary.

Finally, if you need the tangent, divide sine by cosine. If you have any trouble remembering what to divide by what, sine is already above cosine in the table, so you can think of the dividing line between the two as the fraction bar. The tangent of 0°, 45° and 90° are easy to calculate.

• For the tangent of 30° and 60°, you can get a “close enough” answer by approximating 0.9 with 1.
• The actual value of tangent(30°) ≈ 0.57 and tangent(60°) ≈ 1.7. Whew.
• With all of that fresh in our minds, let’s do a sample problem: A child begins to pull a toy behind her with a force of 8 N at an angle of 45° with the ground.

The initial acceleration of the toy is 2 m/s 2, What is the mass of the toy? a) 1.63kgb) 2.84kgc) 4.00kg d) 6.21kg The formula relating force, mass and acceleration is F = Ma. Because we want to use force and acceleration to find the mass, we divide both sides by the acceleration to arrive at the formula M = F/a.

1. As with many physics problems, it’s helpful to draw a sketch of what is going on.
2. Here’s a kid pulling a toy um something or other.
3. Both force and acceleration are given in the problem; however, the 8 N of force being applied to the toy is at a 45° angle.
4. Some of that force is pulling the toy in the y-direction, and some of the force is pulling it in the x-direction.

Because the problem is asking about the toy being pulled along the ground and not up into the air, we’re interested in the x-component of the force. We first remember our rhyme, “syne – point 5, point 7, point 9” and know that we are going to be using cosine in this problem, not sine.

Therefore, to calculate the x-component of the force, we have F x = F * cosine(45°). A quick look at our table of sine and cosine values shows that cos(45°) = 0.7 so F x = F * cosine(45°) = 8 * 0.7 = 5.6. (Know your multiplication tables!) Filling in the formula M = F/a with our newly calculated F x from the problem, we get M = 5.6/2 ≈ 6/2 = 3kg, which is closest to answer b) 2.84kg.

Another example: A tow truck is pulling 25,000 kg car with a tow hook that meets the car at an angle of 30° with the ground. How much force must the tow truck use to pull the car with an initial acceleration of 3 m/s 2 ?

a) 33,612Nb) 50,319Nc) 75,000Nd) 86,206NHere’s a quick picture of our scenario.

Here, the force needed to pull the car in the x-direction can be calculated using the formula F x = Ma. In this scenario, we’re given the mass of the car and the acceleration in the problem. The required force in the x-direction is F x = 25,000kg * 3 m/s 2 = 75,000N.

Expressed in scientific notation, this is 7.5 x 10 4 N. However, because the truck is towing the car at an angle of 30°, the truck is going to need more force than that, because it is acting on the car in both the x- and y-directions. In the previous problem, we saw that F x = F * cos(Θ) where Θ is the degree of the angle, which in this case is 30°.

Reviewing our table of sine and cosine values, we see that cos(30°) ≈ 0.9. Expressed in scientific notation, this is 9 x 10 -1, To solve for F, divide each side of the equation by cos(Θ), which gives the formula, We re-express F x as 75 x 10 3 N rather than 7.5 x 10 4 N to make the division problem a little easier.

### What two sides of a right triangle are compared when using cosine?

Formulas for right triangles – The most important formulas for trigonometry are those for a right triangle. If θ is one of the acute angles in a triangle, then the sine of theta is the ratio of the opposite side to the hypotenuse, the cosine is the ratio of the adjacent side to the hypotenuse, and the tangent is the ratio of the opposite side to the adjacent side.

These three formulas are collectively known by the mnemonic SohCahToa, Besides these, there’s the all-important Pythagorean formula that says that the square of the hypotenuse is equal to the sum of the squares of the other two sides. Along with the knowledge that the two acute angles are complementary, that is to say, they add to 90°, you can solve any right triangle:

If you know two of the three sides, you can find the third side and both acute angles. If you know one acute angle and one of the three sides, you can find the other acute angle and the other two sides.

#### What law should be used to solve a triangle if two sides and an opposite angle or SSA?

Law of Sines – To solve any triangle, you need to know the length of at least one side and two other parts. If one of the other parts is a right angle, then sine, cosine, tangent, and the Pythagorean theorem can be used to solve it. For an oblique triangle, the law of sines or law of cosines ( lesson 6-02 ) must be used. Figure 2: Example of triangle used for law of sines.

## In which case can a triangle be solved by first using the law of cosines?

Law of Cosines – To solve a triangle, a side and two other pieces of information must be known. The law of cosines should be used when two sides and the included angle (SAS) or all three sides (SSS) are known.